IoE (Internet of Everything) Question Bank and Solution (MCQs) for Mumbai University Examination Information Technology Semester 8 - Part 2
Hello Everyone!
This article is based on the Multiple Choice Questions related to IoE.
These MCQs were given as question bank in Mumbai University-BE-Information Technology-Semester 8 Exam for the subject- Internet of Everything.
Column A | Column B |
---|---|
1) Heterogeneity | State of device changes |
2) Enormous scale | Anything can be interconnected with the global information and communication infrastructure |
3) Dynamic changes | Interaction is possible with other devices or service platforms through different networks |
4) Thing related services | The number of devices that need to be managed and that communicate with each other will be atleast an order of magnitude larger than the devices connected to the current internet |
5) Interconnectivity | Provides services such as privacy protection and semantic consistency between physical things and their associated virtual things. |
Solution:
1) Heterogeneity -
Interaction is possible with other devices or service platforms through different networks.
2) Enormous scale -
The number of devices that need to be managed and that communicate with each other will be atleast an order of magnitude larger than the devices connected to the current internet.
3) Dynamic changes -
State of device changes.
4) Thing related services -
Provides services such as privacy protection and semantic consistency between physical things and their associated virtual things.
5) Interconnectivity -
Anything can be interconnected with the global information and communication infrastructure.
Column A | Column B |
---|---|
1) Velocity | Analysis of Data |
2) Variety | Quality of data |
3) Volume | The type and nature of data |
4) Veracity | The speed at which the datais generated and processed |
5) Value | The quantity of generated and stored data |
Solution:
1) Velocity -
The speed at which the datais generated and processed
2) Variety -
The type and nature of data
3) Volume -
The quantity of generated and stored data
4) Veracity -
Quality of data
5) Value -
Analysis of Data
Column A | Column B |
---|---|
1) Sequential | Data alternatively exchanged between Tag and Reader with continuous energy |
2) Half Duplex | Data simultaneously exchanged between Tag and Reader with continuous energy |
3) Full Duplex | Energy transfers while reader and tag transfers data |
Solution:
1) Sequential -
Energy transfers while reader and tag transfers data
2) Half Duplex -
Data alternatively exchanged between Tag and Reader with continuous energy
3) Full Duplex -
Data simultaneously exchanged between Tag and Reader with continuous energy
a. Electrical signal into physical quantity
b. Physical quantity into measurable signals
c. Physical quantity into electric signals
d. Physical quantity into mechanical signals
Solution: b) Physical quantity into measurable signals
a. Equal
b. Ten times
c. Not equal
d. Double
Solution: d) Double
a. One
b. Two
c. Three
d. Four
Solution: a) One
Column A | Column B |
---|---|
1) ROM | Holds incoming data of Modulation and Outgoing Data of Demodulation. |
2) EEPROM | Accommodate security based data. |
3) Data Buffer | Temporary data storage during transponder interrogation and response. |
4) RAM | It needs to ensure that the data are retained when the device in sleep state. |
Solution:
1) ROM - Accommodate security based data.
2) EEPROM - It needs to ensure that the data are retained when the device in sleep state.
3) Data Buffer - Holds incoming data of Modulation and Outgoing Data of Demodulation.
4) RAM - Temporary data storage during transponder interrogation and response.
Column A | Column B |
---|---|
1) Binary search | Each tag reponds in a bit by bit manner. |
2) Bitwise Arbitration | The reader transmits a query, and tags with prefix matching the query repond. |
3) Tree Splitting | The reader sends a serial number to tags, and those with values less than or equal to the serial number reply. |
4) Query Tree | The algorithm performs collisison resolution by splitting collided tags into b disjoint subsets. |
Solution:
1) Binary search - The reader sends a serial number to tags, and those with values less than or equal to the serial number reply.
2) Bitwise Arbitration - Each tag reponds in a bit by bit manner.
3) Tree Splitting - The algorithm performs collisison resolution by splitting collided tags into b disjoint subsets.
4) Query Tree - The reader transmits a query, and tags with prefix matching the query repond.
a. Isotropic antenna
b. Dipole antenna
c. Loop antenna
d. Directional antenna
Solution: a) Isotropic antenna
a. Sensors and actuators
b. Data
c. People and process
d. All of these
Solution: d) All of these
a. Identifying
b. Automatically Deciding
c. Sensing
d. Actuating
e. None of these
f. All of these
Solution: f) All of these
a. 18.5%
b. 20.4%
c. 19.5%
d. 18.4%
Solution: d) 18.4%
a. 36.8%
b. 18.5%
c. 36.6%
d. 18.4%
Solution: a) 36.8%
a. Touch sensor
b. Pressure sensor
c. Temperature sensor
d. Humidity sensor
Solution:
a. True
b. False
Solution: a) True
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